\ANG{
F"ur welches $x$ gilt folgende Gleichung:\qquad
$\D\frac{\D\frac{9}{\frac{6}{x}}}{4}=4\frac{1}{2}$

}
\LSG{
$\D\frac{\D\frac{9}{\frac{6}{x}}}{4}=\frac{\D\frac{9\cdot x}{6}}{4}=
  \frac{\D\frac{3\cdot x}{2}}{4}=
  \frac{3\cdot x}{8}=\frac{9}{2}=\frac{3\cdot 12}{8}
 \quad\DANN\quad x=12$
}
