\ANG{
Berechne den Wert des Terms oder den Wert des Platzhalters $x$:
\begin{enumerate}
 \item $\frac{5}{3} + \frac{7}{6} + \frac{4}{9} - 2 $

 \item $(2\frac{1}{4} - 1\frac{2}{3}) + (3\frac{5}{6} - 2\frac{3}{5}) $

 \item $2\frac{3}{5} = x - 5\frac{17}{34} $

 \item $\frac{4}{9} + \frac{5}{3} + \frac{7}{6}   - 2 $

 \item $(3\frac{1}{4} - 2\frac{2}{3}) + (2\frac{5}{6} - 1\frac{3}{5}) $

 \item $3\frac{3}{5} = x - 4\frac{17}{34} $

 \item $(2\frac{1}{4} - 1\frac{2}{3}) + (5\frac{5}{6} -
 4\frac{3}{5})$

 \item $15\frac{17}{34} = x + 7\frac{3}{5}$

\end{enumerate}}



\LSG{

  \begin{tabular}[t]{llll}

 (a) $1\frac{5}{18}$&

 (b) $1\frac{49}{60}$&

 (c) $x = 8\frac{1}{10}$&

 (d) $1\frac{5}{18}$\\

 (e) $1\frac{49}{60}$&

 (f) $x = 8\frac{1}{10}$&

 (g) $1\frac{49}{60}$&

 (h) $x=7\frac{9}{10}$

  \end{tabular}



}

