
\ANG{

\textbf{Fortlaufend rechnen}

\begin{onehalfspace}
Bestimme jeweils den Wert des Terms in einer fortlaufenden Rechnung:
\end{onehalfspace}

\begin{tabular}{ccccc}
(a) & $2\frac{1}{2}-4\cdot\left(1,5-3\cdot\left(-\frac{1}{2}\right)^{2}\right)$ &  & (b) & $\left[3+\frac{3}{7}\cdot\left(3-\frac{1}{5}\right)\cdot\left(-0,1\right)\right]:2\frac{1}{4}$\tabularnewline
\end{tabular}

}
\LSG{
\begin{enumerate}
\item[(a)] $2\frac{1}{2}-4\cdot\left(1,5-3\cdot\left(-\frac{1}{2}\right)^{2}\right)=2,5-4\cdot\left(1,5-3\cdot0,25\right)
           =2,5-4\cdot0,75=2,5-3=-0,5$
\item[(b)] $\left[3+\frac{3}{7}\cdot\left(3-\frac{1}{5}\right)\cdot\left(-0,1\right)\right]:2\frac{1}{4}=\left[3+\frac{3}{7}\cdot\frac{14}{5}\cdot\left(-\frac{1}{10}\right)\right]:\frac{9}{4}=\left(3-\frac{3}{25}\right)\cdot\frac{4}{9}=\frac{72}{25}\cdot\frac{4}{9}=\frac{32}{25}=1\frac{7}{25}$
\end{enumerate}
}
