\ANG{
Klammere den in eckigen Klammern stehenden Term aus:

\begin{tabular}[t]{llll}
  (a) & $12x^{3}-9x^{2}y+18xy^{2},\quad[3x]$ & 
  (b) & $u^{5}-u^{4}+u^{3},\quad[u^{3}]$ \\
  (c) & $12x^{3}-9x^{2}y+18xy^{2},\quad[12x^{3}]$ & 
  (d) & $u^{5}-u^{4}+u^{3},\quad[u^{5}]$ \\
  (e) & $\D\frac{x^{2}}{8}-\frac{xy}{12}-\frac{x}{4},\quad\left[\frac{x}{4}\right]$ & 
  (f) & $8z^{3}-4z^{2}+2z,\quad[2z]$\rule[-5mm]{0mm}{12mm} \\
  (g) & $\D\frac{x^{2}}{8}-\frac{xy}{12}-\frac{x}{4},\quad\left[-\frac{x}{24}\right]$ & 
  (h) & $8z^{3}-4z^{2}+2z,\quad[8z^{3}]$ \\
\end{tabular}
}
%
\LSG{
\begin{tabular}[t]{llll}
  (a) & $3x(4x^{2}-3xy+6y^{2})$ & 
  (b) & $u^{3}(u^{2}-u+1)$\rule[-4mm]{0mm}{10mm} \\
  (c) & $\D 12x^{3}\left(1-\frac{3y}{4x}+\frac{3y^{2}}{2x^{2}}\right)$ & 
  (d) & $\D u^{5}\left(1-\frac{1}{u}+\frac{1}{u^{2}}\right)$ \\
  (e) & $\D\frac{x}{4}\left(\frac{x}{2}-\frac{y}{3}-1\right)$ & 
  (f) & $2z(4z^{2}-2z+1)$\rule[-5mm]{0mm}{12mm}\\
  (g) & $\D -\frac{x}{24}\left(-3x+2y+6\right)$ & 
  (h) & $\D 8z^{3}\left(1-\frac{1}{2z}+\frac{1}{4z^{2}}\right)$ \\
\end{tabular}
}
