\ANG{
K"urze so weit wie m"oglich:\quad 
 $\D\frac{36a^{3}b-24a^{2}b^{2}}{18ab^{2}-27a^{2}b}$
}
\LSG{ 
$\D\frac{36a^{3}b-24a^{2}b^{2}}{18ab^{2}-27a^{2}b}=
\frac{12a^{2}b(3a-2b)}{9ab(2b-3a)}=
\frac{-4a(2b-3a)}{3(2b-3a)}=-\frac{4a}{3}$
}
