\definecolor{lightestgray}{rgb}{0.96, 0.96, 0.96}
\ANG{
Ergänze die folgenden Aussagen, ohne einen Taschenrechner zu verwenden. \newline \newline
\renewcommand{\arraystretch}{1.6}
\begin{tabular}[h]{|ll|ll|} \hline
(a) $\sqrt 9$ = \colorbox{lightestgray}{\parbox{1cm}{\strut\textcolor{lightestgray}{!!}}},
& da \colorbox{lightestgray}{\parbox{1cm}{\strut\textcolor{lightestgray}{!!}}}² = 9 
& (b) $\sqrt {\colorbox{lightestgray}{\parbox{1cm}{\strut\textcolor{lightestgray}{!!}}}} = 9$,
& da \colorbox{lightestgray}{\parbox{1cm}{\strut\textcolor{lightestgray}{!!}}}² =
  \colorbox{lightestgray}{\parbox{1cm}{\strut\textcolor{lightestgray}{!!}}}²  \\ \hline

(c) $\sqrt \frac 1 {64}$ = \colorbox{lightestgray}{\parbox{1cm}{\strut\textcolor{lightestgray}{!!}}},
& da \colorbox{lightestgray}{\parbox{1cm}{\strut\textcolor{lightestgray}{!!}}}² = $\frac 1 {64}$ 
& (d) $\sqrt {\colorbox{lightestgray}{\parbox{1cm}{\strut\textcolor{lightestgray}{!!}}}} = \frac 5 9$,
& da   \\ \hline

(e) $\sqrt {5 \frac 4 9}$ = \colorbox{lightestgray}{\parbox{1cm}{\strut\textcolor{lightestgray}{!!}}},
& da 
& (f) $\sqrt {0,0004}$ = \colorbox{lightestgray}{\parbox{1cm}{\strut\textcolor{lightestgray}{!!}}},
& da   \\ \hline

(g) $\sqrt {2,25}$ = \colorbox{lightestgray}{\parbox{1cm}{\strut\textcolor{lightestgray}{!!}}},
& da 
& (h) $\sqrt {\colorbox{lightestgray}{\parbox{1cm}{\strut\textcolor{lightestgray}{!!}}}} = 0,4 \quad$ ,
& da   \\ \hline

\end{tabular}
}
\LSG{ 
Ergänze die folgenden Aussagen, ohne einen Taschenrechner zu verwenden. \newline \newline
\renewcommand{\arraystretch}{1.6}
\begin{tabular}[h]{|ll|ll|} \hline
(a) $\sqrt 9$ = 3,
& da $3^2 = 9$ 
& (b) $\sqrt {81} = 9$,
& da $9^2 = 81$  \\ \hline

(c) $\sqrt \frac 1 {64} = \frac 1 8$,
& da $\left( \frac 1 8 \right)^2 = \frac 1 {64}$ 
& (d) $\sqrt {\frac {25}{81}} = \frac 5 9$,
& da $\left( \frac 5 9 \right)^2 = \frac {25}{81}$  \\ \hline

(e) $\sqrt {5 \frac 4 9} = \sqrt{\frac {49} 9} = \frac 7 3$,
& da $\left( \frac 7 3 \right)^2 = \frac {49} 9$
& (f) $\sqrt {0,0004} = 0,02 \quad $,
& da $0,02^2 = 0,0004$  \\ \hline

(g) $\sqrt {2,25} = 1,5 \quad $,
& da $1,5^2 = 2,25$
& (h) $\sqrt{0,16} = 0,4$ ,
& da  $0,4^2 = 0,16$ \\ \hline

\end{tabular}

}
