\ANG{
%
%Sinussatz, Kosinussatz
%
\begin{minipage}[t]{9cm}
Gegeben ist das Viereck $ABCD$ mit der Symmetrieachse $AC$ (siehe Skizze)
und 

$\alpha=70^\circ,~|\overline{AB}|=5{,}2\,{\rm cm},~|\overline{AC}|=11{,}3\,{\rm cm}$.

Berechne $|\overline{BC}|,~|\overline{BD}|$ auf 1 Dezimale und den Winkel 
$\gamma$ auf 1 Grad genau.
\end{minipage}
\hspace{5mm}
\raisebox{-7cm}{\begin{minipage}[t]{7cm}
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\setcoordinatesystem units <5mm,5mm>
\setplotarea x from 0 to 14, y from 0 to 14
\plot 7 3  11 10  7 13  3 10  7 3 /
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\plot 7 1  7 14 /
\plot 3 10  11 10 /
\setsolid
\circulararc 90 degrees from 6 10 center at 7 10
\circulararc 106,26 degrees from 5.67 12 center at 7 13
\circulararc 59,49 degrees from 8 4.75 center at 7 3
\put {A} at 7.5 2.5
\put {B} at 11.5 10
\put {C} at 7.5 13.5
\put {D} at 2.5 10
\put {E} at 7.5 9.4
\put {$\gamma$} at 7.5 12
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\put {\circle*{3}} [Bl] at 6.6 9.6
\put {$\alpha$} at 7.4 4.5
\endpicture
\end{minipage}}
}
\LSG{ $|\overline{BC}|\approx 7{,}6\,cm;
~|\overline{BD}|\approx 6{,}0\,cm;~\gamma\approx 46^\circ$ }