\ANG{
\begin{minipage}[t]{6cm}
%Fl"acheninhalt und Umfang von Kreisen, Thaleskreis, Pythagoras; 
%BIGTEX verwenden
\begin{enumerate}
\item
Berechnen Sie r in Ab\-h"an\-gig\-keit von s.
\item
Berechnen Sie den Fl"a\-chen\-in\-halt der schraffierten 
Fl"ache in Ab\-h"an\-gig\-keit \\
von s!
\item
Berechnen Sie den 
Umfang der schraffierten Fl"ache in Abh"angigkeit von s!
\end{enumerate}
\end{minipage}
\hfill
\begin{minipage}[t]{8cm}
\makebox[0cm]{}\\[-5mm]
\beginpicture

\setcoordinatesystem units <0.9mm,0.9mm> point at 0 0
\setplotarea x from -45 to 45, y from -45 to 45
\unitlength0.9mm
\normalsize

\putrectangle corners at 20 20 and -20 -20


\put {s} at -23 0 
\put {$M_1$} at -16 0

\betweenarrows {s} [l] <1.5mm,0pt> from 20 -20 to 20 20
\betweenarrows {s} [t] <0pt,-1mm> from -20 -20 to 20 -20
\betweenarrows {s} [b] <0pt,1mm> from -20 20 to 20 20

\setlinear
\plot -20 -20 -40 0 -20 20 /

\put {r} at -28 10
\put {r} at -28 -10
\put {$M_2$} at -43 0

\circulararc 180 degrees from 20 20 center at 0 20
\circulararc 180 degrees from 20 -20 center at 20 0
\circulararc 180 degrees from -20 -20 center at 0 -20
\circulararc 180 degrees from -20 20 center at -20 0

\circulararc 90 degrees from -20 20 center at 0 40
\circulararc 90 degrees from -20 -20 center at -40 0
\circulararc 90 degrees from 20 -20 center at 0 -40
\circulararc 90 degrees from 20 20 center at 40 0

\plot 11.7157 0 0 11.7157 /
\plot 12.1612 5 5 12.1612 /
\plot 13.5425 10 10 13.5425 /
\plot 16.0208 15 15 16.0208 /
\plot 12.1612 -5 -5 12.1612 /
\plot 13.5425 -10 -10 13.5425 /

\plot 0 -11.7157 -11.7157 0 /
\plot -5 -12.1612 -12.1612 -5 /
\plot -10 -13.5425 -13.5425 -10 /
\plot -15 -16.0208 -16.0208 -15 /
\plot 5 -12.1612 -12.1612 5 /
\plot 10 -13.5425 -13.5425 10 /

\plot 20 -20 -20 20 /

\put {$\times$} at 0 20
\put {$\times$} at 0 -20
\put {$\times$} at 20 0
\put {$\times$} at -20 0
\put {$\times$} at 0 40
\put {$\times$} at 0 -40
\put {$\times$} at 40 0
\put {$\times$} at -40 0

\endpicture
\end{minipage}

}
\LSG{
$r=\frac{1}{2} \sqrt{2} s$; $A=s^2 (2 - \frac{1}{2} \pi)$; 
$U=\sqrt{2} s \pi$
}
