\ANG{
Berechne jeweils die Spannung der gegebenen Anordnung von Batterien zwischen A und B.
\begin{enumerate}
\item\mbox{}
\begin{center}
    \begin{pspicture}(0,-0.75)(8,0.75)
        \battery[labeloffset=0.85](0,0)(2,0){2\,V}
        \battery[labeloffset=0.85](2,0)(4,0){2\,V}
        \battery[labeloffset=0.85](4,0)(6,0){2\,V}
        \battery[labeloffset=0.85](6,0)(8,0){2\,V}
        \psdots[dotstyle=Bo,dotscale=1.5](0,0)(8,0)
        \rput(0,0.35){A}
        \rput(8,0.35){B}
    \end{pspicture}
\end{center}
\item\mbox{}
\begin{center}
    \begin{pspicture}(0,-0.75)(8,0.75)
        \battery[labeloffset=-0.85](2,0)(0,0){2\,V}
        \battery[labeloffset=-0.85](4,0)(2,0){2\,V}
        \battery[labeloffset=-0.85](6,0)(4,0){2\,V}
        \battery[labeloffset=-0.85](8,0)(6,0){2\,V}
        \psdots[dotstyle=Bo,dotscale=1.5](0,0)(8,0)
        \rput(0,0.35){A}
        \rput(8,0.35){B}
    \end{pspicture}
\end{center}
\item\mbox{}
\begin{center}
    \begin{pspicture}(0,-0.75)(8,0.75)
        \battery[labeloffset=0.85](0,0)(2,0){2\,V}
        \battery[labeloffset=-0.85](4,0)(2,0){2\,V}
        \battery[labeloffset=-0.85](6,0)(4,0){2\,V}
        \battery[labeloffset=0.85](6,0)(8,0){2\,V}
        \psdots[dotstyle=Bo,dotscale=1.5](0,0)(8,0)
        \rput(0,0.35){A}
        \rput(8,0.35){B}
    \end{pspicture}
\end{center}
\item\mbox{}
\begin{center}
    \begin{pspicture}(0,-0.75)(8,0.75)
        \battery[labeloffset=0.85](0,0)(2,0){2\,V}
        \battery[labeloffset=0.85](2,0)(4,0){2\,V}
        \battery[labeloffset=0.85](4,0)(6,0){2\,V}
        \battery[labeloffset=-0.85](8,0)(6,0){2\,V}
        \psdots[dotstyle=Bo,dotscale=1.5](0,0)(8,0)
        \rput(0,0.35){A}
        \rput(8,0.35){B}
    \end{pspicture}
\end{center}
\end{enumerate}
}
\LSG{
$8\,\mathrm{V};-8\,\mathrm{V};0;4\,\mathrm{V}$.
}
