\ANG{
        \parbox[t]{0.35\linewidth}{
            Berechne die Gesamtkapazit\"{a}t der nebenstehenden Anordnung von Kondensatoren.
        }\hspace{0.05\linewidth}
        \parbox[t]{0.6\linewidth}{
          \psset{unit=0.8}
      	  \begin{center}
    		\begin{pspicture}(10,4)

    			\pnode(1,0.5){A0}
    			\pnode(2,0.5){B0}
    			\pnode(5,0.5){C0}
    			\pnode(8,0.5){D0}
    			\pnode(9,0.5){E0}

    			\pnode(1,2){A2}
    			\pnode(2,2){B2}
    			\pnode(5,2){C2}
    			\pnode(8,2){D2}
    			\pnode(9,2){E2}

    			\pnode(1,3.5){A4}
    			\pnode(2,3.5){B4}
    			\pnode(5,3.5){C4}
    			\pnode(8,3.5){D4}
    			\pnode(9,3.5){E4}

    			 \capacitor[dipolestyle=elektor](B0)(C0){$C_1=2{,}0\,\Mmu\mathrm{F}$}
    			 \capacitor[dipolestyle=elektor](C0)(D0){$C_2=8{,}0\,\Mmu\mathrm{F}$}

    			 \capacitor[dipolestyle=elektor](B4)(C4){$C_3=2{,}0\,\Mmu\mathrm{F}$}
    			 \capacitor[dipolestyle=elektor](C4)(D4){$C_4=4{,}0\,\Mmu\mathrm{F}$}
    			\wire(B0)(B4)
    			\wire(D0)(D4)
    			\wire(D2)(E2)
                \wire(A2)(B2)

    			\psdots[dotstyle=Bo](1,2)(9,2)
    			\psdots(2,2)(8,2)

    		\end{pspicture}
    	  \end{center}
        }
}
\LSG{
$C_{12}=\dfrac{C_1\,C_2}{C_1\,C_2}=1{,}6\,\Mmu\mathrm{F}$

$C_{34}= \dfrac{C_3\,C_4}{C_3\,C_4}=1{,}\overline{3}\,\Mmu\mathrm{F}$

$C_{1234} = C_{12}+C_{34} = 2{,}9\,\Mmu\mathrm{F}$
}
