%
\ANG
{
Berechne den Term $\D\frac{6}{\Box}-\D\frac{\Box}{6}$ f"ur $\Box\in\{1;\,2;\,3;\,6\}$. Addiere dann alle Termwerte.
}

\LSG{\mbox{}

\begin{tabular}{c c l c c l}
$\Box =1\,$: & $\D\frac{6}{1}-\D\frac{1}{6}$ & = & $\D\frac{35}{6}$& = & $5\,\D\frac{5}{6}$\\
\\
$\Box =2\,$: & $\D\frac{6}{2}-\D\frac{2}{6}$ & = & $\D\frac{16}{6}$& = & $2\,\D\frac{2}{3}$\\
\\
$\Box =3\,$: & $\D\frac{6}{3}-\D\frac{3}{6}$ & = & $\D\frac{9}{6}$& = & $1\,\D\frac{1}{2}$\\
\\
$\Box =6\,$: & $\D\frac{6}{6}-\D\frac{6}{6}$ & = & $0$\\
\\
\hline
\end{tabular}
\\

$\D\frac{35}{6}+\D\frac{16}{6}+\D\frac{9}{6}+0=\D\frac{60}{6}=10$
}

