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\ANG
{Begr"unde: $\left(\D\frac{\sqrt5-1}{\sqrt2}\right)^{444}\cdot\left(\D\frac{\sqrt5+1}{\sqrt2}\right)^{444}=16\,^{111}$\,.
}
  
\LSG{
$\left(\D\frac{\sqrt5-1}{\sqrt2}\right)^{444}\cdot\left(\D\frac{\sqrt5+1}{\sqrt2}\right)^{444}=
\left(\D\frac{(\sqrt5-1)\cdot(\sqrt5+1)}{\sqrt2\cdot\sqrt2}\right)^{444}=
\left(\D\frac{\sqrt5\,^2-1^2}{\sqrt2\,^2}\right)^{444}=$\\

$=\left(\D\frac{4}{2}\right)^{444}=2\,^{444}=2\,^{4\cdot111}=\left(2^4\right)^{111}=16\,^{111}$\,.
}













